python - Renaming countries in list -


I have a text file, which is formatted with the file name, rating score, and country of origin, which by tab Location on each line is separated: <3p> 

  "3: 0RRBB RTE" (1971) 6.8 West Germany "3K check in" (2002) 4.3 Federal Republic Yugoslavia "3 Mw: Rivers (2008) 7.9 UK "3y" (2008) 8.2 USA "Sun of Three Rock" (1996) 7.8 United States "Third and Bird" (2008) 7.8 UK "3satfestival" (2000) 6.7 Germany

My goal is to calculate the average rating score of each country, which works with the code given below, however, I want to change the names of some countries, such as' West Germany 'to' Germany 'so that their rating scores can be combined together, but I have a code that does not work. Rating score for' West Germany 'and' Germany 'are still calculated separately Can i change MovieRating = collections.namedtuple ('MovieRating', ['countryorigin', 'Ratingcore']) Ratings = {} movie = open ("movieRatingscore.txt", "R") ") # Open the country rating data file for the line in the movie. Lines (): line.rstrip () (moviename, ratingcore, countrymakers) = line.split ('\ t') if countryorigin == 'West Germany' Rating: CountryGuin = 'Germany' Ratingcoreia = Float (Rating Core) Rating Country Rating: Ratings [Countrywide] .append (Ratings) Other: Rating [CountryGermanya] = [Ratingscore] Average = Lambda Goodbye: Zodiac (Alast) / Lane (Alist) average_ratings = [MovieRating (Countrymen, average (Rating [Countrywomen ]) For the country in the rating) Print "\ n Highest Average Movie Rating Country \ n ---------------- -------------- "sorted_ratings = sorted (average_rating, key = lambda countrywide: countrymen.recentingcore, reverse = True) i, for j (sorted_rating): print '% i. % S \ t% g '% (i + 1, j.countryorigin, j.ratingscore)

The easiest way is to use a dictionary to change the words See sample code: 

  dt = {'West Germany': 'Germany', 'other': 'replaced '} For the line in the movie. Roadline (): DT for item: line = line.Raylay (item, dt [item])

-

Comments

Post a Comment

Popular posts from this blog

Member with no value in F# -

After I am trying to convert F # to the following C # code: [StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi)] Private class DOCINFOA {[MarshalAs (UnmanagedType.LPStr)] public string nomeDocumento; [Marshall (UnmanagedType.LPStr)] Public string arquivoSaida; [Marshall (UnmanagedType.LPStr)] Public String Tipodo; } I am doing the following: Named place printer module RawPrinterHelper = [& LT; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.nomeDocumento [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.arquivoSaida [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member This Tipoda [/ code> But I get: One type of definition is necessary for one or more members . Can I vacate these members? you val code> member : [& lt; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [...
Read more

java - Joda Time Interval Not returning what I expect -

मेरे पास निम्न प्रोग्राम है import java.util। *; Import java.text। *; आयात करें org.joda.time। *; सार्वजनिक श्रेणी के स्कोप कंट्रोल {सार्वजनिक स्थिर अंतराल मिलनसार () {दिनांक समय currDate = नया दिनांक समय (2008, 4, 4, 15, 30, 0, 0); दिनांक समय epochDate = नया दिनांकटाइम (2000, 1, 1, 12, 0, 0, 0); अंतराल अंतराल = नया अंतराल (युरोप डेट, करोडेट); वापसी अंतराल; } सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {डबल दिनबात = मिलते समय ()। ToDurationMillis () / 1000/60/60/24; StdOut.println (daysBtween); }} मुझे आउटपुट मिल रहा है: 3016.0 लेकिन जो मैं देख रहा हूं वह है: 3016.1458333333 मैं क्या कर रहा हूँ ? toDurationMillis एक लंबा लौटा देता है, और प्रत्येक प्रभाग को int के रूप में घोषित किया जाता है। जावा इस प्रकार इनट्स को लॉन्ग में परिवर्तित कर देगा और डिवीजन को लंबे समय तक लौटाना होगा। परिणाम को अंत में दोहरे रूप में परिवर्तित करना। डबल्स का उपयोग करके अभिव्यक्ति करने के लिए जावा को बताने के लिए, अभिव्यक्ति के किसी भी घटक को दोहरे रूप में घोषित करें। उदाहरण के लिए: ...
Read more

c# - Showing a SelectedItem's Property -

So I have enabled a rightclick option for my DataGrid. I want to display the only chosen property but it is not behaving like what I would like it to display my name and additional. Public category Paymentinfo {public int PaymentNo {get; Set; } Public string date {get; Set; } Public Double Pay {get; Set; } Public Double Principle {get; Set; } Public Double Interest {get; Set; } Public Double Balance {Received; Set; }} Private Zero MenuItem_OnClick (Object Sender, RoutedEventArgs e) {MessageBox.Show (AmortGrid.SelectedItem.ToString ()); } I'm trying to apply it without using a View Module! If I place a breakpoint where the messagebox and the recipient place it on selected ITEM, then this property will display the payment. A date-payment-principle-interest-balance is the only value that needs payment. Was hoping that it would be something like this MessageBox.Show (AmortGrid.SelectedItem.PaymentNo.ToString ()); When you call ToString () So you get the class typ...
Read more