ios - CALayer zPosition ordering with extremely large values -


I have attended an issue where the core animation appears to be zPosition for my values Ignoring the values ​​become larger.

example

It can be easily replicated

  CGFloat largeZPosition = 1000000000; CALayer * topLayer = ... CALayer * bottomLayer = ... belowLeather.frame = CGFFetset (toplinerframe, 50, 50); TopLayer.zPosition = Big ZPosition + 1; Downlayer ZPosition = Large ZPosition; // Sort arithmetic array in wrong order RootLayer.sublayers = @ [header, bottom letter];  

With small values ​​for z-position, this function, as expected, even if the sub-column array is not sorted correctly, the bottom side is displayed on the top side Such as:

correct

However, the examples shown above , The result is as follows:

Enter image details here

Obviously this is not right.

Question

I'm unable to classify manual inventory for my needs, so I'm relying on zPosition to perform as expected So my question is: How do I work around this problem? Thank you.

That's because Quartzcore has been composed of zPosition to float , therefore it loses the accuracy when CGFloat is double . IEEE single-precision floating-point numbers use 24 bits meaning more accurate, so more than 2 ^ 24 integral numbers can not be properly represented. For example,

  float biggeonation = 1000000000; Float bigZPositionPlus1 = 1000000001; NSLog (@ "% F% F% D", Largegeonation, LargeGroup Plus 1, Biggerency == LargeJustnessPlus1);  

Output

  1000000000.000000 1000000000.000000 1  

The next accurate representational integer is 1000000064.

Note that CALayer.zPosition is defined as CGFloat and it is capable of having an integral value greater than 2 ^ 24 , As long as the underlying CGFloat is able to do this

  layer.zPosition = 1000000001; NSLog (@ "% F", Layer .ZPosition); 64-bit OS X  

Where CGFloat is double , output

  1000000001.000000  

Therefore, on CALayer public purpose - at C class level, it has not been lost. Wherever there is a conversion for single-precision float anywhere in Quartzcor.

I suggest using integral numbers (including the result of extra) which is less than 2 ^ 24. Given that there is a floating-point type in zPosition , you can use small partial values ​​instead of large integral values.


Comments

Popular posts from this blog

Member with no value in F# -

java - Joda Time Interval Not returning what I expect -

c# - Showing a SelectedItem's Property -