xml - How to get the value of a node using for each and if in xpath -


I am new to xpath .. I want to remove all the values ​​of the age which use more than 24 Does the position in xslt 

  & gt; Price bookings & gt; & Lt; Guest & gt; & Lt; GuestCount Age = "24" code = "10" Qty = "1" /> & Lt; GuestCount Age = "26" code = "10" Qty = "1" /> & Lt; GuestCount Age = "3" code = "10" Qty = "1" /> & Lt; / Guest & gt; & Lt; / PriceBooking & gt;

So far I have tried with: - 

   & Lt; / Age & gt; & Lt; / XSL: When & gt; & Lt; XSL: otherwise & gt; & Lt; Sid & gt; Failed to load & lt; / Sid & gt; & Lt; / XSL: otherwise & gt; & Lt; / XSL: Select & gt;

This is always in condition otherwise .. please help with xpath

OK, you need to understand that the for each converts the reference node into a guest element and that's how you relate Paths are required such as 

  & lt; Xsl: when test = "guestlook / @ age and gt; 28" & gt; ... & lt; / Xsl: When & gt;

But the sample you posted has @ edge values ​​of 24, 26, and 3, so the situation is never true.


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