python - crypt does not work in osx, returns wrong value -


I'm using an OSX 10.9 (last version) with the previous Xcode. When I execute the following command: 

  Python-C 'import crypt; Print crypt.crypt ( "test", "$ 6 $ random_salt") '

I get it as an answer: 

  $ 6asQOJRqB1i2

but if I Debian machine (he performs the same in the same version of Python) then I get the following: 

  $ 6 $ random_salt $ sJ0ZOQCUESBs9rYCOLCqGV93zg1cSDgZV / FF6ZBzpnvNUVODwaaVoPV2SiL0ur7Sexh02hMmXdSBOa216GWoh

what's wrong with my machine?

< Implementation of Mac OS X code> crypt () Linux glibc Most "advanced" modes supported by crypt () do not support. It only "conventional crypt () " are the supports that you're here, and "extended crypt () " mode that is compatible with Linux implementation Not so either

If you need to create a portable strong password in Linux and Mac OS X, then you will need to use any other than crypt () .

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