makefile - How to write a recipe common to both .c and cpp files -


I compiled using both .c and .cpp files I want to do the same compiler command like 

  cc = G ++ ... OBJS = Mora. All: $ (oBJS) libMO.so% .o:% .c $ (CC) $ (included) $ (CCFALGS) -k $ (& lt;) -o $ (@) MBMO: $ (OBJS) $ (CC ) $ (LDFALGS) $ (^) -O Dollar (@)

The question now is that the rule / recipe for .cpp files How is it involved? Can we do it in the same rule using the Regex for the prefix?

Is it OK to type another rule / recipe for .cpp ? 

 % O:% .c $ (cc) $ (included) $ (ccfalgs) - c $ (& lt;) -o $ (@)% .o:%. CPP $ (CC) $ (included) $ (CCFALGS) -C $ (& lt;) -o $ (@)

What is the above 1st recipe .cpp files for error because it can not get coding . C file? .ppp

Another rule for .cpp Is it okay to write / prescribe?

Yes it is necessary that you can write a rule for each extension requirement, make the process if you redefine the same pattern.

Will give the error for the 1st referral code .pppp as it file related .c

Make . Cpp will process files independently from the .c files, and vice versa (unless you explicitly tell them, for example, if any . C < / Code> file depends on a .cpp file.)

That said, a small review:

  • Special codes like $ (& lt;) or $ (@) do not require brackets You can directly $ < and $ @ .

  • C and C + code> $ (CPPFALGS) variable (for preprocessor flag, go to your $ (built-in) variable content needed).

  • C $ (CC) and $ (CFLAGS) uses the built-in variable:

    < Pre class = "lang-make prettyprint-override"> cc = $ (csea) ...% .o:% .c $ (cc) $ (cpflegs) $ (cflas) -c $ & lt;

  • Using C ++ in $ (cfa) and $ (CXXFLAGS) built-in: 

     % O:% .cpp $ (CSFA) $ (CPP FALGS) $ (CFFAAGS) -C $ < -O $ @

  • GNU has already made the built-in rule for C and C ++ source files, it is correct to use the above variable, these are normal There is no need to specify the rules at all.


-

Comments

Post a Comment

Popular posts from this blog

Member with no value in F# -

After I am trying to convert F # to the following C # code: [StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi)] Private class DOCINFOA {[MarshalAs (UnmanagedType.LPStr)] public string nomeDocumento; [Marshall (UnmanagedType.LPStr)] Public string arquivoSaida; [Marshall (UnmanagedType.LPStr)] Public String Tipodo; } I am doing the following: Named place printer module RawPrinterHelper = [& LT; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.nomeDocumento [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.arquivoSaida [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member This Tipoda [/ code> But I get: One type of definition is necessary for one or more members . Can I vacate these members? you val code> member : [& lt; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [...
Read more

java - Joda Time Interval Not returning what I expect -

मेरे पास निम्न प्रोग्राम है import java.util। *; Import java.text। *; आयात करें org.joda.time। *; सार्वजनिक श्रेणी के स्कोप कंट्रोल {सार्वजनिक स्थिर अंतराल मिलनसार () {दिनांक समय currDate = नया दिनांक समय (2008, 4, 4, 15, 30, 0, 0); दिनांक समय epochDate = नया दिनांकटाइम (2000, 1, 1, 12, 0, 0, 0); अंतराल अंतराल = नया अंतराल (युरोप डेट, करोडेट); वापसी अंतराल; } सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {डबल दिनबात = मिलते समय ()। ToDurationMillis () / 1000/60/60/24; StdOut.println (daysBtween); }} मुझे आउटपुट मिल रहा है: 3016.0 लेकिन जो मैं देख रहा हूं वह है: 3016.1458333333 मैं क्या कर रहा हूँ ? toDurationMillis एक लंबा लौटा देता है, और प्रत्येक प्रभाग को int के रूप में घोषित किया जाता है। जावा इस प्रकार इनट्स को लॉन्ग में परिवर्तित कर देगा और डिवीजन को लंबे समय तक लौटाना होगा। परिणाम को अंत में दोहरे रूप में परिवर्तित करना। डबल्स का उपयोग करके अभिव्यक्ति करने के लिए जावा को बताने के लिए, अभिव्यक्ति के किसी भी घटक को दोहरे रूप में घोषित करें। उदाहरण के लिए: ...
Read more

c# - Showing a SelectedItem's Property -

So I have enabled a rightclick option for my DataGrid. I want to display the only chosen property but it is not behaving like what I would like it to display my name and additional. Public category Paymentinfo {public int PaymentNo {get; Set; } Public string date {get; Set; } Public Double Pay {get; Set; } Public Double Principle {get; Set; } Public Double Interest {get; Set; } Public Double Balance {Received; Set; }} Private Zero MenuItem_OnClick (Object Sender, RoutedEventArgs e) {MessageBox.Show (AmortGrid.SelectedItem.ToString ()); } I'm trying to apply it without using a View Module! If I place a breakpoint where the messagebox and the recipient place it on selected ITEM, then this property will display the payment. A date-payment-principle-interest-balance is the only value that needs payment. Was hoping that it would be something like this MessageBox.Show (AmortGrid.SelectedItem.PaymentNo.ToString ()); When you call ToString () So you get the class typ...
Read more