Customize Django ContentType -


मेरे पास ऐसा मॉडल है: 

  वर्ग अवरुद्धित मॉडल (मॉडल.मॉडेल): नाम = Models.CharField (max_length = 244) content_type = models.ForeignKey (ContentType) object_id = models.PositiveIntegerField () content_object = generic.GenericForeignKey ('content_type', 'object_id') def __unicode __ (स्वयं): return self.name   
     
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     डीजेंजो व्यवस्थापक में,  content_type  सभी मॉडलों को प्राप्त करें क्या मैं  content_type  
     
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     में  object_id  में केवल वांछित मॉडलों को दे सकता / सकती हूं, इसके बजाय सूची से चुनने का कोई तरीका है  object_id  दर्ज करें 
     
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 पहले से धन्यवाद

यदि आप content_type में केवल कुछ मॉडल चाहते हैं तो आप 

  limit_choices = models.Q (app_label = 'myapp', मॉडल = 'मायमोल्ड') का उपयोग कर सकते हैं। Models.Q (app_label = 'myotherapp', model = 'MyModelOtherModel')) content_type = models.ForeignKey (ContentType, limit_choices_to = limit_choices)

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