python - what is the meaning of module name in imp.load_source? -


stock.py में d: \ stock.py नाम की एक फाइल है, मैं इसे

< Pre> import imp x = imp.load_source ('module_name', 'd: \\ stock.py') x & lt; मॉड्यूल 'module_name' से 'd: /stock.py'> इसे इस रूप में लिखा जा सकता है: y = imp.load_source ('module', 'd: \\ stock.py') y & lt; मॉड्यूल 'मॉड्यूल' से 'd: /stock.py'>

किसी भी स्ट्रिंग को imp.load_source (arg, 'd: \ stock.py') के आरजी में इस्तेमाल किया जा सकता है, इसका अर्थ क्या है?

किसी भी स्ट्रिंग को imp.load_source (arg, 'd: \ stock.py') के arg में उपयोग किया जा सकता है इसका अर्थ क्या है?

एक समझदार मूल्य का उपयोग करने से त्रुटियों और डीबग करना आसान समझ जाता है। साथ ही, आप __ मुख्य __ ब्लॉक को चालू कर सकते हैं।


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