mysql - grails database-migration-plugin: dbm-gorm-diff generates changesets for existing indexes -


सेटअप:

डेटाबेस-माइग्रेशन: 1.4.0

mysql: 5.6 .15

grails: 2.4.2

मेरा कार्यप्रवाह यह था:

  1. एक प्रारंभिक changelog.groovy w / dbm- उत्पन्न- gorm-
  2. मॉडल को संशोधित करें
  3. डीबीएम-जीर-अंतर Change1.groovy

नवनिर्मित परिवर्तन सेट में createIndex डायरेक्टिविट्स में पहले से मौजूद इंडिंस को संदर्भित किया गया है।

एफडब्ल्यूआईडब्लू, डाटाबेसएचांगेलओग की तलाश में है, डुप्लिकेट आईडी के साथ एक समान पंक्ति भी है, EXECTYPE: 'एक्सीक्यूट'।

यह बी 4 () की सूचना मिली थी, लेकिन अनुमान लगाई गई थी।

सुराग?

धन्यवाद


-

Comments

Post a Comment

Popular posts from this blog

php - Select box validation (in laravel) -

I have a text that includes text input and selection box. I was trying to apply Laravel validation. I now want to retain user input values ​​if the verification does not succeed. I'm able to get it on the input box, but not on the selection box. This is my code {{form :: select ('vehicles_year'), how the first selected value (in the selection box) will show. $ Model year, '-1', ['id' = & gt; 'Vehicles_year'])}} & lt; Span class = "help-block" id = "vehicles_year_error" & gt; @if ($ errors-> ('vehicles_year')) {{$ errors- & gt; First ('vehicles_year')}} @endif & lt; / Span & gt; -1 I am the default value key when I am showing the form load. What I do is that I add the "default" option which is "nothing" Is set to. In the validity rules, I say this value is necessary. If the user does not choose any of the other options, the verification fails. $ op...
Read more

pandas - Iterate on Groupby Object's fields -

I want to be able to iterate over a group object: grouped = Df Groupby ('zzz') question_list = [a, b, c] How do I get a list of values ​​for: grouped .grouped.b grouped.c but using a for-loop? You can either remove such a key print Df Groupby ('zzz'). Groups.keys () To capture the grouped. You can do this ... print df.groupby ('Zzz') group ['A'] or you can open the key, For this type of group key, in df.groupby group ('Zzz'): print key # group key Is a dataframe related to
Read more

Creating a sparse matrix in Matlab with a specified number of independent Bernoulli +-1 nonzero entries -

How can we create matrix x, 1000 by 1000 in the matteback, which is sparse, say Are, 5% of independent Bernoulli + 1 nonzero entries? I.e. In such a matrix, rho = = X Choose 5% of irregular elements n = Numel (x); Ind = Randie (n, round (.05 * n), 1); Assign these elements with random variables x (ind) = binorend (1, .5, length), 1) * 2-1; Check for more information To prevent duplicate rand numbers, from the Statistics Toolbox, or randperm as mentioned in some, or something like this Ind = []; T = round (.05 * n); T1 = length (IND); While T1 & LT; T Ind (end + 1: t0) = rand (n, tt-1, 1); Ind = Unique (Ind); T1 = length (IND); End
Read more