storyboard - How to Assign a class to a custom UIView in Swift? -


I am trying to create a custom framework so that I can use the @IB design to present my view in the storyboard Can I Generally you can click on the view of the storyboard and select a class from the drop-down in the inspector since I will have to assign my custom framework by hanging, now I can create a custom subview within my framework And to have my class allocated is also that (which is a square from the graphical cycle counter downloaded from cocoapods JWGCircleCounter ..) How do I do this in Swift XCode 6 Yak There is no code here for my custom framework: 

  Import UIKit @IBDesignable square CircleTimer: UIView {Override Work Layouts SubViews () {SuperLatesBuivius () var Outer Circle = Uviqualor ( JWGCrackQuent) (frame CGRactam: 22, 137, 125, 125) // How can I decide how to assign a square, I'm not even sure about reducing the frame after specifying the T work. / Code>   
 
 
 You have code> JWGCircleCounter  as  JWGCircleCounter   UIView . As should be made of  intializer  init (frame: CGRect).  You can call this to create an example 
 
 In addition to  fast  
  circle CircleTimer: UIView {Override function layoutSubviews () {OuterCircle at Super.layoutSubviews (): JWGCircleCounter = JWGCircleCounter (frame: CGRectMake (22, 137, 125, 125)) // How to assign a square to my estimate, of course it does not work is. I am also sure that where class self.addSubview is not to delicate the frame (outerCircle)}

JWGCircleCounter subclass of after the UIView and override it already in init (frame :) so that you can ask to make it an example.

And note that you do not always have the exact opposite of sub class ( JWGCircleCounter ) superclass ( UIView ).

Edit : You can try coco fond

Choose your project file (Blue on top right) and select Build Settings Go to . Then, for both project file (blue) and custom framework target, set 'Allow non-modular to include in Framework module' and set yes


-

Comments

Post a Comment

Popular posts from this blog

Member with no value in F# -

After I am trying to convert F # to the following C # code: [StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi)] Private class DOCINFOA {[MarshalAs (UnmanagedType.LPStr)] public string nomeDocumento; [Marshall (UnmanagedType.LPStr)] Public string arquivoSaida; [Marshall (UnmanagedType.LPStr)] Public String Tipodo; } I am doing the following: Named place printer module RawPrinterHelper = [& LT; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.nomeDocumento [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member this.arquivoSaida [& LT; MarshalAs (UnmanagedType.LPStr) & gt;] Member This Tipoda [/ code> But I get: One type of definition is necessary for one or more members . Can I vacate these members? you val code> member : [& lt; StructLayout (LayoutKind.Sequential, charset = CharSet.Ansi) & gt;] Type DOCINFOA = [...
Read more

java - Joda Time Interval Not returning what I expect -

मेरे पास निम्न प्रोग्राम है import java.util। *; Import java.text। *; आयात करें org.joda.time। *; सार्वजनिक श्रेणी के स्कोप कंट्रोल {सार्वजनिक स्थिर अंतराल मिलनसार () {दिनांक समय currDate = नया दिनांक समय (2008, 4, 4, 15, 30, 0, 0); दिनांक समय epochDate = नया दिनांकटाइम (2000, 1, 1, 12, 0, 0, 0); अंतराल अंतराल = नया अंतराल (युरोप डेट, करोडेट); वापसी अंतराल; } सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {डबल दिनबात = मिलते समय ()। ToDurationMillis () / 1000/60/60/24; StdOut.println (daysBtween); }} मुझे आउटपुट मिल रहा है: 3016.0 लेकिन जो मैं देख रहा हूं वह है: 3016.1458333333 मैं क्या कर रहा हूँ ? toDurationMillis एक लंबा लौटा देता है, और प्रत्येक प्रभाग को int के रूप में घोषित किया जाता है। जावा इस प्रकार इनट्स को लॉन्ग में परिवर्तित कर देगा और डिवीजन को लंबे समय तक लौटाना होगा। परिणाम को अंत में दोहरे रूप में परिवर्तित करना। डबल्स का उपयोग करके अभिव्यक्ति करने के लिए जावा को बताने के लिए, अभिव्यक्ति के किसी भी घटक को दोहरे रूप में घोषित करें। उदाहरण के लिए: ...
Read more

c# - Showing a SelectedItem's Property -

So I have enabled a rightclick option for my DataGrid. I want to display the only chosen property but it is not behaving like what I would like it to display my name and additional. Public category Paymentinfo {public int PaymentNo {get; Set; } Public string date {get; Set; } Public Double Pay {get; Set; } Public Double Principle {get; Set; } Public Double Interest {get; Set; } Public Double Balance {Received; Set; }} Private Zero MenuItem_OnClick (Object Sender, RoutedEventArgs e) {MessageBox.Show (AmortGrid.SelectedItem.ToString ()); } I'm trying to apply it without using a View Module! If I place a breakpoint where the messagebox and the recipient place it on selected ITEM, then this property will display the payment. A date-payment-principle-interest-balance is the only value that needs payment. Was hoping that it would be something like this MessageBox.Show (AmortGrid.SelectedItem.PaymentNo.ToString ()); When you call ToString () So you get the class typ...
Read more