Strange behavior of strsplit() in R? -


मैं स्ट्रिंग x = "a, b," को विभाजित करना चाहूंगा strsplit () का उपयोग करके वेक्टर c ("a", "b", "") में ।

परिणाम है: < / P> 

  & gt; strsplit (x, ',') [[1]] [1] "a" "b"

मुझे यह पसंद है तीसरा घटक (रिक्त स्ट्रिंग या नल)।

फ़ंक्शन read.csv (x) उस का प्रबंधन कर सकता है, लेकिन फिर भी मुझे लगता है कि strsplit () जैसा कि मैंने उम्मीद की थी व्यवहार करना चाहिए c ("a", "b", "") देता है।

शायद strsplit () का कोई विकल्प नहीं है मुझे नहीं पता

इसी तरह यह काम करता है और मदद (strsplit) में प्रलेखित है: 

  ध्यान दें कि इसका अर्थ है कि यदि (गैर खाली) स्ट्रिंग की शुरुआत में एक मैच होता है, तो आउटपुट का पहला तत्व '' '' है, लेकिन अगर इसके अंत में एक मैच होता है स्ट्रिंग, आउटपुट मैच के समान के समान है I

आप str_split से stringr पैकेज का उपयोग करना चाह सकते हैं: 

  & gt; आवश्यकता (स्ट्रिंगर) & gt; Str_split ("a, b,", ",") [[1]] [1] "एक" "बी" "" & gt; Str_split ("a, b", ",") [[1]] [1] "एक" "बी" & gt; Str_split (", a, b", ",") [[1]] [1] "" "एक" "बी" & gt; Str_split (", a, b ,,,", ",") [[1]] [1] "एक" "बी" "" "" ""

-

Comments

Post a Comment

Popular posts from this blog

php - Select box validation (in laravel) -

I have a text that includes text input and selection box. I was trying to apply Laravel validation. I now want to retain user input values ​​if the verification does not succeed. I'm able to get it on the input box, but not on the selection box. This is my code {{form :: select ('vehicles_year'), how the first selected value (in the selection box) will show. $ Model year, '-1', ['id' = & gt; 'Vehicles_year'])}} & lt; Span class = "help-block" id = "vehicles_year_error" & gt; @if ($ errors-> ('vehicles_year')) {{$ errors- & gt; First ('vehicles_year')}} @endif & lt; / Span & gt; -1 I am the default value key when I am showing the form load. What I do is that I add the "default" option which is "nothing" Is set to. In the validity rules, I say this value is necessary. If the user does not choose any of the other options, the verification fails. $ op...
Read more

pandas - Iterate on Groupby Object's fields -

I want to be able to iterate over a group object: grouped = Df Groupby ('zzz') question_list = [a, b, c] How do I get a list of values ​​for: grouped .grouped.b grouped.c but using a for-loop? You can either remove such a key print Df Groupby ('zzz'). Groups.keys () To capture the grouped. You can do this ... print df.groupby ('Zzz') group ['A'] or you can open the key, For this type of group key, in df.groupby group ('Zzz'): print key # group key Is a dataframe related to
Read more

Creating a sparse matrix in Matlab with a specified number of independent Bernoulli +-1 nonzero entries -

How can we create matrix x, 1000 by 1000 in the matteback, which is sparse, say Are, 5% of independent Bernoulli + 1 nonzero entries? I.e. In such a matrix, rho = = X Choose 5% of irregular elements n = Numel (x); Ind = Randie (n, round (.05 * n), 1); Assign these elements with random variables x (ind) = binorend (1, .5, length), 1) * 2-1; Check for more information To prevent duplicate rand numbers, from the Statistics Toolbox, or randperm as mentioned in some, or something like this Ind = []; T = round (.05 * n); T1 = length (IND); While T1 & LT; T Ind (end + 1: t0) = rand (n, tt-1, 1); Ind = Unique (Ind); T1 = length (IND); End
Read more